1樓:莪曖孫悟箜
1 √32-3√1/2+√2
2 √12+√27/√3-√1/3×√123 √50+√30/√8-4
4 √24+√216/√6+5
5 (√6-2√15)×√3-6√1/26 √2/3-4√216+43√1/67 √8+√30-√2
8 √1/7+√63-√112
9 √40-5√1/10+√10
10 √2+√8/√2
11 √2/9+√50+√32
12 (1-√3)(√3+2)
13 (√8+3√6)÷√2-√3×√0.714 (-3+√6)(-3-√6)-(√3-1/√3)²15 ³√0.125-√3 1/16+³√(1-7/8)²16 √2/3-√216+42√1/6
2樓:轉身淚傾城
3樓:匿名使用者
什麼計算題,自己買些書看看吧
數學初二實數計算題及答案(一百道) 100
4樓:匿名使用者
(1)99²-2.99² (2)80×3.5²+160×3.5×1.5+80×1.5² (3)181²-61²÷301²-181²
(4)5x-5y+5z (5)-5a²+25a-5a (6)2a(b+c)-3(b+c) (7)(ab+a)+(b+1)
(8)-4m³+16m³-28m (9)16x-25x³y² (10)36m²a-9m²a²-36m²
√12+√27/√3-√1/3×√12
√50+√30/√8-4
(√6-2√15)×√3-6√1/2
√2/3-4√216+43√1/6
√8+√30-√2
√40-5√1/10+√10
√2+√8/√2
√2/9+√50+√32
(1-√3)(√3+2)
(√8+3√6)÷√2-√3×√0.7
(-3+√6)(-3-√6)-(√3-1/√3)²
³√0.125-√3 1/16+³√(1-7/8)²
√2/3-√216+42√1/6
解方程√3 x-1=√2 x
求x注:x全部不在根號內
√(1/2x)^2+10/9x^2
=√[1/(4x^2)+10/(9x^2)]
=√49/36x^2
若x>0,=7/(6x)
若x<0,=-7/(6x)
√a^4mb^2n+1
=√(a^2mb^n)^2+1
=a^2mb^n+1
√(4a^5+8a^4)(a^2+3a+2)
=√[4a^4(a+2)][(a+2)(a+1)]
=√[4a^4(a+2)^2(a+1)]
=2a^2(a+2)√(a+1)
. 3√(1/6)-4√(50)+30√(2/3)
答案3√(1/6)-4√(50)+30√(2/3)
= 3×√6/6-4×5√2+30×√6/3
=√6/2-20√2+10√6
2. (1-根號2)/2乘以(1+根號2)/2
題是這樣的二分之一減根號2乘以二分之一加根號2
答案:(1-根號2)/2乘以(1+根號2)/2
=(1-√2)*(1-√2)/4
=(1-2)/4
=-1/4
1.3√(1/6)-4√(50)+30√(2/3) 答案3√(1/6)-4√(50)+30√(2/3) = 3×√6/6-4×5√2+30×√6/3 =√6/2-20√2+10√6 2. (1-根號2)/2乘以(1+根號2)/2 題是這樣的二分之一減根號2乘以二分之一加根號2 答案:
(1-根號2)/2乘以(1+根號2)/2 =(1-√2)*(1-√2)/4 =(1-2)/4 =-1/4 3.√(1/2x)^2+10/9x^2 √[(1/2x)^2+10/9x^2] =√(x^2/4+10x^2/9) =√(9x^2/36+40x^2/36) =√(49x^2/36) =7x/6; 4.√a^4mb^2n+1(a、b為正數) [√(a^4mb^2n)]+1(a、b為正數) =a^2mb^n+1; 5.
√(4a^5+8a^4)(a^2+3a+2)(a>=0) √[(4a^5+8a^4)(a^2+3a+2)](a>=0) =√[4a^4(a+2)(a+2)(a+1)] =√[(2a^2)^2(a+2)^2(a+1)] =2a^2(a+2)√(a+1). 太多了呀,只能這樣了,我還有事 您好! ①5√8-2√32+√50 =5*3√2-2*4√2+5√2 =√2(15-8+5) =12√2 ②√6-√3/2-√2/3 =√6-√6/2-√6/3 =√6/6 ③(√45+√27)-(√4/3+√125) =(3√5+3√3)-(2√3/3+5√5) =-2√5+7√5/3 ④(√4a-√50b)-2(√b/2+√9a) =(2√a-5√2b)-2(√2b/2+3√a) =-4√a-6√2b ⑤√4x*(√3x/2-√x/6) =2√x(√6x/2-√6x/6) =2√x*(√6x/3) =2/3*x*√6 ⑥(x√y-y√x)÷√xy =x√y÷√xy-y√x÷√xy =√x-√y ⑦(3√7+2√3)(2√3-3√7) =(2√3)^2-(3√7)^2 =12-63 =-51 ⑧(√32-3√3)(4√2+√27) =(4√2-3√3)(4√2+3√3) =(4√2)^2-(3√3)^2 =32-27 =5 ⑨(3√6-√4)² =(3√6)^2-2*3√6*√4+(√4)^2 =54-12√6+4 =58-12√6 ⑩(1+√2-√3)(1-√2+√3) =[1+(√2-√3)][1-(√2-√3)] =1-(√2-√3)^2 =1-(2+3+2√6) =-4-2√6 1.
=5√5 - 1/25√5 - 4/5√5 =√5*(5-1/25-4/5) =24/5√5 2.=√144+576 =√720 =12√5 3.)√(8/13)^2-(2/13)^2 = √(8/13+2/13)(8/13-2/13) =(2/13)√15
5樓:藍星哲陌
一本參考書bai 還有就是實數計算掌握熟練就du好 為什麼要做zhi這麼多?好孩子dao啊~~
初二數學實數計算題
6樓:匿名使用者
求x注:x全部不在根號內
√(1/2x)^2+10/9x^2
=√[1/(4x^2)+10/(9x^2)]=√49/36x^2
若x>0,=7/(6x)
若x<0,=-7/(6x)
√a^4mb^2n+1
=√(a^2mb^n)^2+1
=a^2mb^n+1
√(4a^5+8a^4)(a^2+3a+2)=√[4a^4(a+2)][(a+2)(a+1)]=√[4a^4(a+2)^2(a+1)]
=2a^2(a+2)√(a+1)
. 3√(1/6)-4√(50)+30√(2/3)答案3√(1/6)-4√(50)+30√(2/3)= 3×√6/6-4×5√2+30×√6/3=√6/2-20√2+10√6
2. (1-根號2)/2乘以(1+根號2)/2題是這樣的二分之一減根號2乘以二分之一加根號2答案:(1-根號2)/2乘以(1+根號2)/2=(1-√2)*(1-√2)/4
=(1-2)/4
=-1/4
1.3√(1/6)-4√(50)+30√(2/3) 答案3√(1/6)-4√(50)+30√(2/3) = 3×√6/6-4×5√2+30×√6/3 =√6/2-20√2+10√6 2. (1-根號2)/2乘以(1+根號2)/2 題是這樣的二分之一減根號2乘以二分之一加根號2 答案:
(1-根號2)/2乘以(1+根號2)/2 =(1-√2)*(1-√2)/4 =(1-2)/4 =-1/4 3.√(1/2x)^2+10/9x^2 √[(1/2x)^2+10/9x^2] =√(x^2/4+10x^2/9) =√(9x^2/36+40x^2/36) =√(49x^2/36) =7x/6; 4.√a^4mb^2n+1(a、b為正數) [√(a^4mb^2n)]+1(a、b為正數) =a^2mb^n+1; 5.
√(4a^5+8a^4)(a^2+3a+2)(a>=0) √[(4a^5+8a^4)(a^2+3a+2)](a>=0) =√[4a^4(a+2)(a+2)(a+1)] =√[(2a^2)^2(a+2)^2(a+1)] =2a^2(a+2)√(a+1). 太多了呀,只能這樣了,我還有事 您好! ①5√8-2√32+√50 =5*3√2-2*4√2+5√2 =√2(15-8+5) =12√2 ②√6-√3/2-√2/3 =√6-√6/2-√6/3 =√6/6 ③(√45+√27)-(√4/3+√125) =(3√5+3√3)-(2√3/3+5√5) =-2√5+7√5/3 ④(√4a-√50b)-2(√b/2+√9a) =(2√a-5√2b)-2(√2b/2+3√a) =-4√a-6√2b ⑤√4x*(√3x/2-√x/6) =2√x(√6x/2-√6x/6) =2√x*(√6x/3) =2/3*x*√6 ⑥(x√y-y√x)÷√xy =x√y÷√xy-y√x÷√xy =√x-√y ⑦(3√7+2√3)(2√3-3√7) =(2√3)^2-(3√7)^2 =12-63 =-51 ⑧(√32-3√3)(4√2+√27) =(4√2-3√3)(4√2+3√3) =(4√2)^2-(3√3)^2 =32-27 =5 ⑨(3√6-√4)² =(3√6)^2-2*3√6*√4+(√4)^2 =54-12√6+4 =58-12√6 ⑩(1+√2-√3)(1-√2+√3) =[1+(√2-√3)][1-(√2-√3)] =1-(√2-√3)^2 =1-(2+3+2√6) =-4-2√6 1.
=5√5 - 1/25√5 - 4/5√5 =√5*(5-1/25-4/5) =24/5√5 2.=√144+576 =√720 =12√5 3.)√(8/13)^2-(2/13)^2 = √(8/13+2/13)(8/13-2/13) =(2/13)√15 參考資料:
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